(2x^2-x-3)(3x+4)=

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Solution for (2x^2-x-3)(3x+4)= equation: 


Simplifying
(2x2 + -1x + -3)(3x + 4) = 0

Reorder the terms:
(-3 + -1x + 2x2)(3x + 4) = 0

Reorder the terms:
(-3 + -1x + 2x2)(4 + 3x) = 0

Multiply (-3 + -1x + 2x2) * (4 + 3x)
(-3(4 + 3x) + -1x * (4 + 3x) + 2x2 * (4 + 3x)) = 0
((4 * -3 + 3x * -3) + -1x * (4 + 3x) + 2x2 * (4 + 3x)) = 0
((-12 + -9x) + -1x * (4 + 3x) + 2x2 * (4 + 3x)) = 0
(-12 + -9x + (4 * -1x + 3x * -1x) + 2x2 * (4 + 3x)) = 0
(-12 + -9x + (-4x + -3x2) + 2x2 * (4 + 3x)) = 0
(-12 + -9x + -4x + -3x2 + (4 * 2x2 + 3x * 2x2)) = 0
(-12 + -9x + -4x + -3x2 + (8x2 + 6x3)) = 0

Combine like terms: -9x + -4x = -13x
(-12 + -13x + -3x2 + 8x2 + 6x3) = 0

Combine like terms: -3x2 + 8x2 = 5x2
(-12 + -13x + 5x2 + 6x3) = 0

Solving
-12 + -13x + 5x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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